Answer
(a) See the graph.
(b) $(-6,6)$
Work Step by Step
(b)
$x=r~cos~θ$
$x=-6\sqrt 2~cos(-\frac{\pi}{4})=-6\sqrt 2(\frac{\sqrt 2}{2})=-6$
$y=r~sin~θ$
$y=-6\sqrt 2~sin(-\frac{\pi}{4})=-6\sqrt 2(-\frac{\sqrt 2}{2})=6$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 8 - Review - Exercises - Page 622: 6
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