Answer
(a) See the graph.
(b) $(x^2+y^2)^2=4xy$
Work Step by Step
(b)
$x=r~cos~θ$
$y=r~sin~θ$
$r^2=x^2+y^2$
$r^2=4~sin~2θ$
$r^2=4~sin~θ~cos~θ$
$r^2=4~\frac{y}{r}~\frac{x}{r}$
$r^4=4xy$
$(x^2+y^2)^2=4xy$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 8 - Review - Exercises - Page 622: 22
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