Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Review - Exercises - Page 622: 2

Answer

(a) See the graph. (b) $(-4\sqrt 2,-4\sqrt 2)$

Work Step by Step

(b) $x=r~cos~θ$ $x=8~cos~(-\frac{3\pi}{4})=8(-\frac{\sqrt 2}{2})=-4\sqrt 2$ $y=r~sin~θ$ $y=8~sin~(-\frac{3\pi}{4})=8(-\frac{\sqrt 2}{2})=-4\sqrt 2$
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