Answer
(a) See the graph.
(b) $(-4\sqrt 2,-4\sqrt 2)$
Work Step by Step
(b)
$x=r~cos~θ$
$x=8~cos~(-\frac{3\pi}{4})=8(-\frac{\sqrt 2}{2})=-4\sqrt 2$
$y=r~sin~θ$
$y=8~sin~(-\frac{3\pi}{4})=8(-\frac{\sqrt 2}{2})=-4\sqrt 2$
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