Answer
16
Work Step by Step
We can rewrite $i+1$ as $\sqrt 2cis(\pi/4)$
Using De moivre's theorem,
$(\sqrt 2cis(\pi/4))^8= 2^4*cis(8*(\pi/4))$
Which simplifies to 16.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 8 - Review - Exercises - Page 622: 36
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