Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Review - Exercises - Page 622: 4

Answer

(a) See the graph. (b) $(\frac{\sqrt 3}{2},-\frac{3}{2})$

Work Step by Step

(b) $x=r~cos~θ$ $x=-\sqrt 3~cos~(\frac{2\pi}{3})=-\sqrt 3(-\frac{1}{2})=\frac{\sqrt 3}{2}$ $y=r~sin~θ$ $y=-\sqrt 3~sin~(\frac{2\pi}{3})=-\sqrt 3(\frac{\sqrt 3}{2})=-\frac{3}{2}$
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