Chapter 8 - Review - Exercises - Page 622: 18

(a) See the graph (b) $x^2+(y-\frac{3}{2})^2=\frac{9}{4}$

(b) $y=r~sin~θ$ $\frac{y}{r}=sin~θ$ $x^2+y^2=r^2$ $r=3(\frac{y}{r})$ $r^2=3y$ $x^2+y^2-3y=0$ $x^2+y^2-3y+\frac{9}{4}-\frac{9}{4}=0$ $x^2+(y-\frac{3}{2})^2=(\frac{3}{2})^2$