Answer
(a) See the graph.
(b) $(x^2+y^2)^3=16x^2y^2$
Work Step by Step
(b)
$x=r~cos~θ$
$y=r~sin~θ$
$r^2=x^2+y^2$
$r=2~sin~2θ$
$r=4~sin~θ~cos~θ$
$r=4\frac{y}{r}\frac{x}{r}$
$r^3=4xy~~$ (Square both sides)
$r^6=16x^2y^2$
$(x^2+y^2)^3=16x^2y^2$
