Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Review - Exercises - Page 622: 1

Answer

(a) See the graph. (b) $(6\sqrt 3,6)$

Work Step by Step

(b) $x=r~cos~θ$ $x=12~cos~\frac{\pi}{6}=12(\frac{\sqrt 3}{2})=6\sqrt 3$ $y=r~sin~θ$ $y=12~sin~\frac{\pi}{6}=12(\frac{1}{2})=6$
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