Answer
(a) See the graph.
(b) $x^2-y^2=1$
Work Step by Step
(b)
$x=r~cos~θ$
$y=r~sin~θ$
$r^2=x^2+y^2$
$r^2=sec~2θ$
$r^2=\frac{1}{cos~2θ}$
$r^2=\frac{1}{cos^2θ-sin^2θ}$
$r^2=\frac{1}{\frac{x^2}{r^2}-\frac{y^2}{r^2}}$
$r^2=\frac{r^2}{x^2-y^2}$
$x^2-y^2=1$
