Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.6 - The Binomial Theorem - 12.6 Exercises - Page 887: 45

Answer

$(2a+b)^{3} $

Work Step by Step

$(a+b)^{n}=\left(\begin{array}{l} n\\ 0 \end{array}\right)a^{n}+\left(\begin{array}{l} n\\ 1 \end{array}\right)a^{n-1}b+\left(\begin{array}{l} n\\ 2 \end{array}\right)a^{n-2}b^{2}+\cdots+\left(\begin{array}{l} n\\ n \end{array}\right)b^{n}$ ------------------- $8a^{3}=(2a)^{3}$ and $b^{3}=(b)^{3}$ lead us to check whether the expression equals $(2a+b)^{3} $ $(2a+b)^{3} =\left(\begin{array}{l} 3\\ 0 \end{array}\right)(2a)^{3}b^{0}+\left(\begin{array}{l} 3\\ 1 \end{array}\right)(2a)^{2}b^{1}+\left(\begin{array}{l} 3\\ 2 \end{array}\right)(2a)^{1}b^{2}+\left(\begin{array}{l} 3\\ 3 \end{array}\right)(2a)^{0}b^{3}$ $=8a^{3}+12a^{2}b+6ab^{2}+b^{3}$ It does.
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