Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 26

Answer

$x=-1$ $y=-2$ $z=4$

Work Step by Step

Express x from the second equation. $2x+y-z=-8 $ $-x+y+z=3 \rightarrow x=y+z-3$ $-2x+4z=18$ Substitute $ x=y+z-3$ into the first and the third equation. $2(y+z-3)+y-z=-8 $ $-2(y+z-3)+4z=18$ Simplify. $3y+z=-2$ $-2y+2z=12$ Multiply the first equation by -2. $3y+z=-2 \rightarrow -6y-2z=4$ Add the equations to eliminate z. $-8y=16$ $y=-2$ Substitute for y and solve for x and z. $3y+z=-2 \rightarrow z=4$ $x=y+z-3 \rightarrow x=-1$
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