Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 16

Answer

$2x + z = 1$ $3z = -3$

Work Step by Step

To eliminate the y-term from the third equation, there are two steps: 1. Double the first equation, triple the third equation, then add them 2. Double the second equation and subtract the third equation from its result. Given: $x - 3y + 2z = -1$ $y + z = -1$ $2y - z = 1$ 1. $2x - 6y + 4z = -2$ +($6y - 3z = 3$) $2x + z = 1$ 2. $2y + 2z = -2$ -($2y - z = 1$) $3z = -3$ New system: $2x + z = 1$ $3z = -3$
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