Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 10

(4,3,4)

Solving the last equation by dividing by 3 we get z is 4. When we substitute z = 4 into the second equation we get $2y-4=2$ Solving we get y = 3. Substituting both variables into the first equation we get $x-6+12=10$. Solving, x is 4.