Answer
$y - z = 1$
$7y + 2z = 16$
Work Step by Step
To eliminate the x-term from the third equation, there are two steps:
1. Triple the first equation and subtract the third equation from its result.
2. Triple the second equation and subtract the third equation from its result.
Given:
$2x + y - 3z= 5$
$2x + 3y + z = 13$
$6x - 5y - z = 7$
1.
$6x +3y - 9z= 15$
-($6x - 5y - z = 7$)
$8y - 8z = 8$
$y - z = 1$
2.
$6x + 9y + 3z = 39$
-($6x - 5y - z = 7$)
$14y + 4z = 32$
$7y + 2z = 16$
New system:
$y - z = 1$
$7y + 2z = 16$
