Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 17

Answer

$x=2$ $y=1$ $z=-3$

Work Step by Step

Express z from the second equation. $x-y-z=4$ $2y+z=-1\rightarrow z=-1-2y$ $-x+y-2z=5$ Substitute $ z=-1-2y$ into the first and the third equation. $x-y-(-1-2y)=4$ $-x+y-2(-1-2y)=5$ Simplify. $x+y=3$ $-x+5y=3$ Add the equations to eliminate x. $6y=6$ $y=1$ Substitute for y and solve for x and z. $z=-3$ $x=2$
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