Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 20

Answer

$x=2$ $y=3$ $z=-2$

Work Step by Step

Express z from the second equation. $x-2y+3z=-10$ $3y+z=7\rightarrow z=7-3y$ $x+y-z=7$ Substitute $ z=7-3y$ into the first and the third equation. $x-2y+3(7-3y)=-10$ $x+y-(7-3y)=7$ Simplify. $x-11y=-31$ $x+4y=14$ Multiply the second equation by -1. $x+4y=14 \rightarrow -x-4y=-14$ Add the equations to elimiate x. $-15y=-45$ $y=3$ Substitute for y and solve for x and z. $z=7-3y\rightarrow z=-2$ $x+4y=14\rightarrow x=2$
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