Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 697: 21

Answer

$x=1$ $ y=2$ $z=1$

Work Step by Step

Express x from the first equation. $x+y+z=4 \rightarrow x=4-y-z$ $x+3y+3z=10$ $2x+y-z=3$ Substitute $ x=4-y-z$ into the second and the third equation. $4-y-z+3y+3z=10$ $2(4-y-z)+y-z=3$ Simplify. $2y+2z=6$ $-y-3z=-5$ Multiply the second equation by 2. $-y-3z=-5 \rightarrow -2y-6z=-10$ Add the equations to eliminate y. $-4z=-4$ $z=1$ Substitute for z and solve for x and y. $-y-3z=-5 \rightarrow y=2$ $ x=4-y-z\rightarrow x=1$
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