#### Answer

$\frac{(y-2)}{(3-y)}$

#### Work Step by Step

Looking at the numerator:
Combine $1-\frac{2}{y}$ by multiplying $1$ by $\frac{y}{y}$. This then becomes: $\frac{y-2}{y}$.
Looking at the denominator:
Combine $\frac{3}{y}-1$ by multiplying $1$ by $\frac{y}{y}$. This then becomes: $\frac{3-y}{y}$.
The fraction is now:
$=\frac{\frac{y-2}{y}}{\frac{3-y}{y}}$
Divide the fractions:
$=\frac{(y-2)y}{y(3-y)}$
Cancel the common factor of $y$:
$=\frac{(y-2)}{(3-y)}$