Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 33



Work Step by Step

$\dfrac{x+3}{4x^{2}-9}\div\dfrac{x^{2}+7x+12}{2x^{2}+7x-15}$ Factor the denominator of the first fraction and the numerator and the denominator of the second fraction: $\dfrac{x+3}{(2x+3)(2x-3)}\div\dfrac{(x+4)(x+3)}{(2x-3)(x+5)}=...$ Evaluate the division and simplify: $...=\dfrac{(x+3)(2x-3)(x+5)}{(2x+3)(2x-3)(x+4)(x+3)}=\dfrac{x+5}{(2x+3)(x+4)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.