## Precalculus: Mathematics for Calculus, 7th Edition

$\frac{x+4}{x+3}$
$1+\frac{1}{x+3}$ Convert element to fraction: $=\frac{1}{1}+\frac{1}{x+3}$ Find the least common denominator (i.e. $x+3$): $=\frac{x+3}{x+3}+\frac{1}{x+3}$ Combine the fractions: $=\frac{x+3+1}{x+3}$ Simplify the fraction: $=\frac{x+4}{x+3}$