Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 25



Work Step by Step

$=\frac{4x}{x^2-4}\times\frac{x+2}{16x}$ Multiply the two: $=\frac{4x(x+2)}{16x(x^2-4)}$ Cancel out the x-variable: $=\frac{4(x+2)}{16(x^2-4)}$ Factorise the $x^2-4$: $=\frac{4(x+2)}{16(x+2)(x-2)}$ Cancel out the $x+2$: $=\frac{4}{16(x-2)}$ Simplify the fraction: $=\frac{1}{4(x-2)}$
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