Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 26



Work Step by Step

$=\frac{x^2-25}{x^2-16}\times\frac{x+4}{x+5}$ Multiply the two fractions: $=\frac{(x^2-25)(x+4)}{(x^2-16)(x+5)}$ Factorise $x^2-25$: $=\frac{(x-5)(x+5)(x+4)}{(x^2-16)(x+5)}$ Factorise $x^2-16$: $=\frac{(x-5)(x+5)(x+4)}{(x-4)(x+4)(x+5)}$ Simplify the fraction: $=\frac{(x-5)}{(x-4)}$
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