Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 35

Answer

$\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}=x^{2}(x+1)$

Work Step by Step

$\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}$ Factor the denominator of the denominator: $\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}=\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{(x+1)^{2}}}=...$ Evaluate the division: $...=\dfrac{x^{3}(x+1)^{2}}{x(x+1)}=...$ Simpify: $...=x^{2}(x+1)$
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