## Precalculus: Mathematics for Calculus, 7th Edition

$\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}=x^{2}(x+1)$
$\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}$ Factor the denominator of the denominator: $\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{x^{2}+2x+1}}=\dfrac{\dfrac{x^{3}}{x+1}}{\dfrac{x}{(x+1)^{2}}}=...$ Evaluate the division: $...=\dfrac{x^{3}(x+1)^{2}}{x(x+1)}=...$ Simpify: $...=x^{2}(x+1)$