Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 34

Answer

$\dfrac{2x+1}{2x^{2}+x-15}\div\dfrac{6x^{2}-x-2}{x+3}=\dfrac{1}{(2x-5)(3x-2)}$

Work Step by Step

$\dfrac{2x+1}{2x^{2}+x-15}\div\dfrac{6x^{2}-x-2}{x+3}$ Factor the denominator of the first fraction and the numerator of the second fraction: $\dfrac{2x+1}{(2x-5)(x+3)}\div\dfrac{(3x-2)(2x+1)}{x+3}=...$ Evaluate the division: $...=\dfrac{(2x+1)(x+3)}{(2x-5)(x+3)(3x-2)(2x+1)}=...$ Simplify: $...=\dfrac{1}{(2x-5)(3x-2)}$
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