Answer
$x$
Work Step by Step
$\frac{x^2-x-6}{x^2+2x}\times\frac{x^3+x^2}{x^2-2x-3}$
Factorise the fraction $\frac{x^2-x-6}{x^2+2x}$:
$=\frac{(x-3)(x+2)}{x(x+2)}$
Simplify the fraction:
$=\frac{x-3}{x}$
Factorise the fraction $\frac{x^3+x^2}{x^2-2x-3}$:
$=\frac{x^2(x+1)}{(x-3)(x+1)}$
Simplify the fraction:
$=\frac{x^2}{(x-3)}$
Multiply the two results:
$=\frac{x-3}{x}\times\frac{x^2}{(x-3)}$
$=\frac{x^2(x-3)}{x(x-3)}$
Cancel out $x-3$:
$=\frac{x^2}{x}$
Simplify the fraction:
$=x$
