#### Answer

$\frac{y-6}{2y+1}$

#### Work Step by Step

factor both the numerator and denominator:
from : $\frac{y^{2}-3y-18}{2y^{2}+7y+3}$
to: $\frac{(y-6)(y+3)}{(2y+1)(y+3)}$
then cancel like terms: (y+3):
$\frac{(y-6)}{(2y+1)}$

Published by
Brooks Cole

ISBN 10:
1305071751

ISBN 13:
978-1-30507-175-9

$\frac{y-6}{2y+1}$

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