Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 65

Answer

$log_2[x(3x-2)^4]$

Work Step by Step

$8log_2\sqrt {3x-2}-log_2(\frac{4}{x})+log_24=log_2(3x-2)^4-log_2(\frac{4}{x})+log_24=log_2[(3x-2)^4\times \frac{x}{4}\times4]=log_2[x(3x-2)^4]$
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