Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 33

Answer

$3a$

Work Step by Step

With $8=3^3$, then $\ln8 = \ln(2^3)$ Recall that $\ln \left(M^r\right) = r \ln M$ Using the rule above gives: $\ln{\left(2^3\right)} = 3 \ln2$ With $\ln2=a$, then $3 \ln2 = 3a$ Therefore, $\ln8 = \boxed{3a}$
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