Answer
$1$
Work Step by Step
$\because \log_a M-\log_a N = \log_a\left(\dfrac{M}{N}\right)$
$\therefore \log_6 18 - \log_6 3 = \log_6 \left(\dfrac{18}{3}\right) = \log_6 6$
$\because \log_a a = 1$
$\therefore \log_6 6 = 1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 21
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