## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\ln{x}+x$
Recall: $\log_a{(MN)} = \log_a{M}+\log_a{N}$ Using the rule above gives: $\ln(x e^x) = \ln{x}+\ln{\left(e^x\right)}$ Recall also that $\ln{e^x} = x$ Thus, $\ln{(x e^x)} = \boxed{\ln{x}+x}$