Answer
$1+\ln(x)$
Work Step by Step
$\log_a (MN) = \log_a M+\log_a N$
$\therefore \ln(ex) = \ln(e) + \ln(x)$
Recall that $\ln(e) = 1$.
Thus,
$\ln(ex) = \boxed{1+\ln(x)}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 41
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