Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 19

Answer

$1$

Work Step by Step

$\because \log_a M+\log_a N = \log_a (MN)$ $\therefore \log_8 2 + \log_8 4 = \log_8 (2 \cdot 4) = \log_8 8$ $\because \log_a a = 1$ $\therefore \log_8 8 = 1$
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