Answer
$\begin{bmatrix}
{6}&{32}\\
{1}&{3}\\
{-2}&{-4}\end{bmatrix}$
Work Step by Step
Since $A$ is a $3 \times 3$ matrix and $B$ is a $3 \times 2$ matrix, the product $AB$ is defined as a $3 \times 2$ matrix.
$$AB=\begin{bmatrix}
{(4)(2)+(-2)(1)+3(0)}&{4(6)+(-2)(-1)+3(2)}\\
{0(2)+(1)(1)+(2)(0)}&{0(6)+(1)(-1)+(2)(2)}\\
{(-1)(2)+0(1)+1(0)}&{(-1)(6)+0(-1)+1(2)}\end{bmatrix} \\=\begin{bmatrix}
{8-2+0}&{24+2+6}\\
{0+1+0}&{0-1+4}\\
{-2+0+0}&{-6+0+2}\end{bmatrix} \\=\begin{bmatrix}
{6}&{32}\\
{1}&{3}\\
{-2}&{-4}\end{bmatrix}$$