Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.4 Matrix Algebra - 10.4 Assess Your Understanding - Page 777: 15

Answer

$\begin{bmatrix} 28 & -9\\ 4 & 23 \end{bmatrix}$

Work Step by Step

Since, matrix $A$ is a $ 2 \times 3$ matrices and matrix $C$ is a $3 \times 2$ , we know that $AC$, is defined. Multiply to obtain: $AC=\begin{bmatrix} 0 & 3 & -5\\ 1 & 2 & 6 \end{bmatrix} \begin{bmatrix} 4 & 1\\ 6 & 2\\ -2 & 3 \end{bmatrix} \\=\begin{bmatrix} {0(4)+3(6)+(-5)(-2)}&{0(1)+3(2)+(-5)(3)}\\ {1(4)+2(6)+6(-2)}&{1(1)+2(2)+6(3)}\end{bmatrix}\\=\begin{bmatrix} 28 & -9\\ 4 & 23 \end{bmatrix}$
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