## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Chapter 10 - Systems of Equations and Inequalities - Section 10.4 Matrix Algebra - 10.4 Assess Your Understanding - Page 777: 23

#### Answer

$\begin{bmatrix} {-13}&{7}&{-12}\\ {-18}&{10}&{-14}\\ {17}&{-7}&{34}\end{bmatrix}$

#### Work Step by Step

In Problems 17 and 18, we found: $CA=\begin{bmatrix} {1}&{14}&{-14}\\ {2}&{22}&{-18}\\ {3}&{0}&{28}\end{bmatrix}$ and $CB=\begin{bmatrix} {14}&{7}&{-2}\\ {20}&{12}&{-4}\\ {-14}&{7}&{-6}\end{bmatrix}$ Now, calculate $CA-CB=\begin{bmatrix} {1-14}&{14-7}&{-14-(-2)}\\ {2-20}&{22-12}&{-18-(-4)}\\ {3-(-14)}&{0-7}&{28-(-6)}\end{bmatrix}\\=\begin{bmatrix} {1-14}&{14-7}&{-14+2}\\ {2-20}&{22-12}&{-18+4}\\ {3+14}&{0-7}&{28+6}\end{bmatrix} \\=\begin{bmatrix} {-13}&{7}&{-12}\\ {-18}&{10}&{-14}\\ {17}&{-7}&{34}\end{bmatrix}$

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