Answer
$\begin{bmatrix}
{9}&{2}\\
{34}&{13}\\
{47}&{20}\end{bmatrix}$
Work Step by Step
Since $A$ is a $3 \times 3$ matrix and $B$ is a $3 \times 2$ matrix, the product $AB$ is defined as a $3 \times 2$ matrix.
$$AB=\begin{bmatrix}
{(1)(1)+(0)(6)+(1)(8)}&{(1)(3)+0(2)+1(-1)}\\
{(2)(1)+(4)(6)+(1)(8)}&{(2)(3)+(4)(2)+(1)(-1)}\\
{(3)(1)+(6)(6)+(1)(8)}&{(3)(3)+(6)(2)+(1)(-1)}\end{bmatrix} \\=\begin{bmatrix}
{1+0+8}&{3+0+(-1)}\\
{2+24+8}&{6+8+(-1)}\\
{3+36+8}&{9+12+(-1)}\end{bmatrix} \\=\begin{bmatrix}
{9}&{2}\\
{34}&{13}\\
{47}&{20}\end{bmatrix}$$