Answer
$\left[\begin{array}{ccc}
{1}&{14}&{-14}\\
{2}&{22}&{-18}\\
{3}&{0}&{28}\end{array}\right]$
Work Step by Step
Since, matrix $C$ is a $ 3 \times 2$ matrix and matrix $A$ is $2 \times 3$ , then we know that $CA$, is defined and is a $3 \times 3$ matrix.
Multiply the matrices to obtain:
$CA=\left[\begin{array}{ll}
4 & 1\\
6 & 2\\
-2 & 3
\end{array}\right]\left[\begin{array}{lll}
0 & 3 & -5\\
1 & 2 & 6
\end{array}\right] \\=\left[\begin{array}{ccc}
{(4)(0)+1(1)}&{(4)(3)+(1)(2)}&{(4)(-5)+1(6)}\\
{(6)(0)+2(1)}&{6(3)+2(2)}&{(6)(-5)+(2)(6)}\\
{(-2)(0)+(3)(1)}&{(-2)(3)+(3)(2)}&{-2(-5)+3(6)}\end{array}\right] \\=\left[\begin{array}{ccc}
{1}&{14}&{-14}\\
{2}&{22}&{-18}\\
{3}&{0}&{28}\end{array}\right]$
