Answer
$\begin{bmatrix}
15 & 21 & -16\\
22 & 34 & -22\\
-11 & 7 & 22
\end{bmatrix}$
Work Step by Step
Since, $A+B$ is a $2 \times 3$ matrix and matrix $C$ is $3 \times 2$, we know that $C(A+B)$, is defined and is a $3 \times 3$ matrix.
$A+B=\left[\begin{array}{lll}
0+4 & 3+1 & -5+0\\
1+(-2) & 2+3 & 6+(-2)
\end{array}\right] \\=\left[\begin{array}{lll}
4 & 4 & -5\\
-1 & 5 & 4
\end{array}\right]$
Now, $C(A+B)=\left[\begin{array}{ll}
4 & 1\\
6 & 2\\
-2 & 3
\end{array}\right]\left[\begin{array}{lll}
4 & 4 & -5\\
-1 & 5 & 4
\end{array}\right] \\=\left[\begin{array}{lll}
16-1 & 16+5 & -20+4\\
24-2 & 24+10 & -30+8\\
-8-3 & -8+15 & 10+12
\end{array}\right] \\=\begin{bmatrix}
15 & 21 & -16\\
22 & 34 & -22\\
-11 & 7 & 22
\end{bmatrix}$
