Answer
$$\begin{bmatrix}
{-1}&{2}&{-1}\\
{0}&{-12}&{3}\\
{15}&{30}&{0}\end{bmatrix}$$
Work Step by Step
Since $A$ is a $3 \times 2$ matrix and $B$ is a $2 \times 3$ matrix, the product $AB$ is defined as a $3 \times 3$ matrix.
$$AB=\begin{bmatrix}
{(1)(2)+(-1)(3)}&{1(8)+(-1)(6)}&{(1)(-1)+(-1)(0)}\\
{(-3)(2)+2(3)}&{(-3)(8)+2(6)}&{(-3)(-1)+2(0)}
\\{(0)(2)+(5)(3)}&{(0)(8)+5(6)}&{0(-1)+(5)(0)}\end{bmatrix}\\=\begin{bmatrix}
{2-3}&{8-6}&{-1+0}\\
{-6+6}&{-24+12}&{3+0}
\\{0+15}&{0+30}&{0+0}\end{bmatrix}\\=\begin{bmatrix}
{-1}&{2}&{-1}\\
{0}&{-12}&{3}\\
{15}&{30}&{0}\end{bmatrix}$$
