#### Answer

$I10^{-\frac {d}{10}}$

#### Work Step by Step

$d=10\log \dfrac {I}{I_{0}}\Rightarrow \log \dfrac {I}{I_{0}}=\dfrac {d}{10}\Rightarrow \dfrac {I}{I_{0}}=10^{\frac {d}{10}}\Rightarrow I_{0}=I10^{-\frac {d}{10}}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$I10^{-\frac {d}{10}}$

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