Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 492: 43

Answer

$\approx 2.102$

Work Step by Step

$10e^{3x-7}=5\Rightarrow e^{3x-7}=\dfrac {1}{2}\Rightarrow 3x-7=\ln \dfrac {1}{2}\Rightarrow x=\dfrac {7+\ln \dfrac {1}{2}}{3}\approx 2.102$
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