#### Answer

$\approx -0.484$

#### Work Step by Step

$e^{2-x}=12\Rightarrow \dfrac {e^{2}}{ex}=12\Rightarrow e^{x}=\dfrac {e^{2}}{12}\Rightarrow x=\ln \left( \dfrac {e^{2}}{12}\right) \approx -0.484$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\approx -0.484$

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