Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 492: 41


$\approx -0.484$

Work Step by Step

$e^{2-x}=12\Rightarrow \dfrac {e^{2}}{ex}=12\Rightarrow e^{x}=\dfrac {e^{2}}{12}\Rightarrow x=\ln \left( \dfrac {e^{2}}{12}\right) \approx -0.484$
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