Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 492: 55


$\dfrac {10^{0.25}-7}{2}$

Work Step by Step

$\log \left( 2x+7\right) =0.25\Rightarrow 2x+7=10^{0.25}\Rightarrow x=\dfrac {10^{0.25}-7}{2}$
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