Answer
$\approx -2.487$
Work Step by Step
$6^{x-3}=3^{4x+1}\Rightarrow \dfrac {6^{x}}{6^{3}}=3^{4x}\times 3\Rightarrow \left( \dfrac {6}{3^{4}}\right) ^{x}=648\Rightarrow $
$x=\log _{\dfrac {6}{81}}648\approx -2.487$
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