## Precalculus (6th Edition)

Doesn’t have any real $x$.
$\left( \dfrac {1}{2}\right) ^{x}+2=0\Rightarrow \left( \dfrac {1}{2}\right) ^{x}=-2\Rightarrow x=\log _{\dfrac {1}{2}}\left( -2\right)$ This equation doesn’t have any real solution