Answer
$2$
Work Step by Step
$\ln \left( 6x\right) -\ln \left( x+1\right) =\ln 4\Rightarrow \ln \dfrac {6x}{x+1}=\ln 4\Rightarrow \dfrac {6x}{x+1}=4$
$\Rightarrow 6x=4x+4\Rightarrow 2x=4\Rightarrow x=2$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 492: 63
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