Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 492: 63



Work Step by Step

$\ln \left( 6x\right) -\ln \left( x+1\right) =\ln 4\Rightarrow \ln \dfrac {6x}{x+1}=\ln 4\Rightarrow \dfrac {6x}{x+1}=4$ $\Rightarrow 6x=4x+4\Rightarrow 2x=4\Rightarrow x=2$
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