#### Answer

$3$

#### Work Step by Step

$\log _{16}\sqrt {x+1}=\dfrac {1}{4}=\sqrt {x+1}=16^{\dfrac {1}{4}}=2\Rightarrow x+1=2^{2}\Rightarrow x=2^{2}-1=3$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$3$

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