Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises: 66

Answer

$a\left( e^{\frac {S}{a}}-1\right) $

Work Step by Step

$a\ln \left( 1+\dfrac {n}{a}\right) =S\Rightarrow \ln \left( 1+\dfrac {n}{a}\right) =\dfrac {S}{a}\Rightarrow 1+\dfrac {n}{a}=e^{\frac {S}{a}}\Rightarrow n=a\left( e^{\frac {S}{a}}-1\right) $
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