Answer
$-2\pm2i$
Work Step by Step
Step 1. Given $(x+4)(x+2)=2x$, we have $x^2+6x+8=2x\longrightarrow x^2+4x+8=0$, thus $a=1, b=4, c=8$
Step 2. Use the quadratic formula, we have $x=\frac{-4\pm\sqrt {4^2-4(1)(8)}}{2}=\frac{-4\pm\sqrt {-16}}{2}=-2\pm2i$