Answer
$\frac{\sqrt 5\pm3}{2}$
Work Step by Step
Step 1. Given $x^2-\sqrt 5x-1=0$, we have $a=1, b=-\sqrt 5, c=-1$
Step 2. Use the quadratic formula, we have $x=\frac{\sqrt 5\pm\sqrt {(-\sqrt 5)^2-4(1)(-1)}}{2}=\frac{\sqrt 5\pm\sqrt {5+4}}{2}=\frac{\sqrt 5\pm3}{2}$
